What is the $\mathrm{pH}$ of a $\pu{5M}$ solution of hydrochloric acid?
So in order to solve this, apparently all you need to do is plug it into the equation:
$$\mathrm{pH} = -\log[\ce{H3O+}]$$
where the concentration of $\ce{H3O+}$ is $\pu{5M}$. But why can we assume this? Don’t we need to create an ice table from $\ce{HCl + H2O-> H3O+ + Cl-}$ and use the $K_\text{a}$ value of $\ce{HCl}$ to solve this?
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