I understand that we need to add $\ce{FeBr3}$ while brominating benzene in order to polarize the bromine molecule. However, we do not need to add such a Lewis Acid in the case of phenol, because it is activated by the $\ce{-OH}$ group, and so polarizes the bromine molecule on its own. Anisole is also highly activated, however we still add $\ce{FeBr3}$ in order to brominate it. Why? (An answer which compares bromination in phenol and anisole will be highly appreciated.)
Subscribe to:
Post Comments (Atom)
digital communications - Understanding the Matched Filter
I have a question about matched filtering. Does the matched filter maximise the SNR at the moment of decision only? As far as I understand, ...
-
Are there any statistics as to what percentage of Chabad still believes that their Rebbe is the Messiah? Is it the majority or simply a very...
-
I know (from a friend who attends) that the Maimonides, the school founded by R' Soloveitchik, observes Thanksgiving. Did the Rav, or an...
-
I'd like to know if I can put ~じゃん at the end of every adjective, if there are any exceptions to that usage, and if it's different f...
No comments:
Post a Comment