Sunday, March 10, 2019

physical chemistry - How does conductivity work for non-redoxed ions?



Related (very similar, but here I want a mechanism) https://physics.stackexchange.com/q/21827/7433



By the Kohlrausch law, all ions contribute to the conductivity of an electrolyte.


Now, as I understand it, the mechanism of conduction in an electrolyte is thus:



  • Ions migrate in solution

  • These ions get reduced or oxidized at the electrodes and converted to electrons


  • These electrons continue down the wire, leading to an increased/maintained conductivity/current


But, this mechanism doesn't work for ions which do not get redoxed--movement of ions in the solution cannot be translated to movement of electrons in the wire and thus it seems (to me) that conductivity should not increase.


But ions like $\ce{NO3-}$ have a comparable $\lambda$ (ionic molar conductivity)--so they experimentally do increase conductivity.


What is the mechanism for conduction via these ions?



Answer



This can arise due to ion-ion interactions brought on by Coulombic fields.


A proper explanation is rooted in transport phenomena. Unfortunately chemists are largely not taught this, but chemical engineers do get the opportunity.


Under standard conditions, ions in a solution will take a random walk during diffusion. This results in no net movement of our ions over some span of time. Such a system perturbed by an applied electric field will cause ions to preferentially move in one direction, we say the ions will drift. We say they have a drift velocity. These velocities are affected by a number of parameters, as there is still continual collision, but we can say that the mobilities will be unequal for ions of unequal sizes.


Different mobilities mean concentration gradients form and charge separation too. Typically we use an electroneutrality field as a reasonable approximation to allow analytic solutions for various equations. This field depends on all the ionic fluxes present and as such will affect the total measurable current.



The result is simple: the introduction of any ion will cause a perturbation in the field that all the ions encounter in solution.


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