How would $\ce{H2SO4}$ react to heat ? I assume that it would form toxic sulfur (di/tri)oxide, but I can't find any information on this.
I'm concerned about fire hazards specifically, so assume very intense heating and very low concentration.
Answer
Sulfuric acid, $\ce{H2SO4}$, having an enthalpy of formation of $-814$ kJ/mol, is quite stable and won't decompose easily.
The decomposition of $\ce{H2SO4}$ to $\ce{H2O}$ and $\ce{SO3}$ is predominant between $400$ and $700$ K. The formation of a small amount of gaseous sulfuric acid can be observed. Above $673$ K, the equilibrium constant of the reaction R1 becomes higher than 1 and increases rapidly.
$$\ce{H2SO4 <=> H2O + SO3}\tag{R1}$$
The second process is the reduction of sulfur trioxide to $\ce{SO2}$. This endothermic reaction needs a high temperature to take place, the equilibrium constant of the reaction R2 being higher that 1 above 1050 K.
$$\ce{SO3 <=> SO2 + \dfrac12O2}\tag{R2}$$
So, you only have to worry when the temperature reaches $400$ K, or $127^\circ\mathrm{C}$ (false precision).
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