Monday, July 29, 2019

homework - Hybridization of tetraamminecopper(II) sulfate


$\ce{Cu^2+} $ has 9 electrons and a d-orbital and is almost completely filled (except 1 electron vacant) and $\ce{NH3}$ donates an electron eventually forming $\mathrm{sp^3}$ hybrid orbitals.


But it has a square planar geometry hence completely contradicting the above reasoning. Please explain what the hybridization is?




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