Sunday, September 8, 2019

signal analysis - Bandwidth of a trimmed sinus wave


I generate a sinus which duration is 15ms and frequeuncy of 13KHz. Is its bandwidth is (1/15ms) ? Or in other words, BW = 66.6Hz? I ask that because I have two freqs in my system: 13K & 13.1K. I know that they are seperated by 100Hz. And as the tone I generate have a lower duration I think it spreads into its friend area.



Answer



The spectrum of your windowed sinusoid is just a shifted sinc function (assuming a rectangular window). If T=0.015s is the length of the signal then the magnitude of the spectrum at positive frequencies is given by


S(f)=T|sinc((ff0)T)|,f>0


with f0 the frequency of the sinusoid, and where I use the definition sinc(x)=sin(πx)/(πx). So with Δf=100Hz (the distance to the other sinusoid), you get a relative attenuation of


|sinc(ΔfT)|=0.2122113.5dB


So at the frequency of the neighboring sinusoid, the spectrum of the other (finite length) sinusoid is about 13.5dB lower.



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