Thursday, January 9, 2020

How is it that the equilibrium constant does not depend on the mechanism?


For a reaction of the form



$$\ce{aA + bB <=> cC + dD}$$


the equilibrium constant is


$$K_c=\frac{[\ce{C}]^c[\ce{D}]^d}{[\ce{A}]^a[\ce{B}]^b}$$


regardless of the mechanism of the reaction. Why is this the case?


I've seen derivations that use a reaction in one elementary step to demonstrate this, but this obviously doesn't work in general. The sample reaction used was $\ce{N2O4 <=> 2NO2}$.




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