FFT: Does the result of $N log_2(N)$ stand for total operations or (complex) adds and multiplies?

Calculate the amount of operations you need for the Fast Fourier Transform.

Take $N=2048 \times 2048$

$N\dfrac{\log(N)}{\log(2)}$

$\dfrac{\log(2048 \times 2048)}{\log(2)}$ is 22.

$(2048 \times 2048) \dfrac{\log(2048 \times 2048)}{\log(2)}$ is 92274688.

But does $92274688$ stand for total operations or $92274688$ adds AND $92274688$ multiiplications?

So the total amount of operations is $2\times 92274688=184549376$.