Thursday, January 31, 2019

matlab - Using Spreading spectral with Maximal likelihood


As asked here, HERE if we have the signal


x = 
[0.7 + 0.7i;

0.7 - 0.7i;
-0.7 + 0.7i;
-0.7 -0.7i];

Which was spread over code c and transmitted over channel H whose dimension is [4x4], so the convolution of signal after spreading will become:


r = reshape(H*reshape(x,4,[]),[],1);

comparing it with signal without spreading, it was


 r = H*x; 


That was explained well in the above link.


My question, suppose I am using Maximum likelihood estimation, in case if we didn't spread the signal, we will check the likelhood compared with the channel H, but what's about after using spreading ? how will become the channel ? It supposed to be a vector of [16x1], is that right ? but how will it be ?


thank you!



Answer



H was not reshaped, as you see in your command r = reshape(H*reshape(x,4,[]),[],1);, you reshaped the data itself.


In that case, you are going to add noise, then using ML estimation based on the received data. So that, H will be H without changing, what will be changed is the received data, you can reshape it similar to that way in the transmitter reshape(y,4,[]), where y is the received data, then reshape the results again into [16 x 1].


Good luck


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