Sunday, February 2, 2020

inorganic chemistry - Reaction of chlorine with hot/cold solution of hydroxide


When chlorine reacts with cold solution of say potasium hydroxide, the disproportionation goes to lower oxidation states:


$\ce{Cl2 + 2 KOH -> KCl + KClO + H2O} $



Whilst with hot solution the oxidation state of chlorine goes up to $+V$:


$\ce{3 Cl2 + 6 KOH -> KClO3 + 5 KCl + 3 H2O} $


Why is that? Does the heat make the oxidation to higher ox. states easier?




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