I read from a source that 2-iodopropane undergoes iodoform reaction. What reaction mechanism is undergone here, and why does this happen?
Yes, Aaron.
It will.
Because Iodide is very good leaving group. In iodoform test, we use base... which will convert 2-iodopropane into propan-2-ol. The latter will give haloform the same way as ethyl alcohol and any other methyl ketone does! 
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